3n^2+3n-28=2n^2

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Solution for 3n^2+3n-28=2n^2 equation:


Simplifying
3n2 + 3n + -28 = 2n2

Reorder the terms:
-28 + 3n + 3n2 = 2n2

Solving
-28 + 3n + 3n2 = 2n2

Solving for variable 'n'.

Combine like terms: 3n2 + -2n2 = 1n2
-28 + 3n + 1n2 = 2n2 + -2n2

Combine like terms: 2n2 + -2n2 = 0
-28 + 3n + 1n2 = 0

Factor a trinomial.
(-7 + -1n)(4 + -1n) = 0

Subproblem 1

Set the factor '(-7 + -1n)' equal to zero and attempt to solve: Simplifying -7 + -1n = 0 Solving -7 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1n = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1n = 0 + 7 -1n = 0 + 7 Combine like terms: 0 + 7 = 7 -1n = 7 Divide each side by '-1'. n = -7 Simplifying n = -7

Subproblem 2

Set the factor '(4 + -1n)' equal to zero and attempt to solve: Simplifying 4 + -1n = 0 Solving 4 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1n = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1n = 0 + -4 -1n = 0 + -4 Combine like terms: 0 + -4 = -4 -1n = -4 Divide each side by '-1'. n = 4 Simplifying n = 4

Solution

n = {-7, 4}

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